Power Screw (Square Thread)

torque-power

Verified build 4 relations · 4 identities proven · 1 modeling step · 6 parity samples

Car jacks, bench vises, lathe lead screws, linear actuators, clamping fixtures, piano stools — whenever a machine needs to turn modest torque into crushing linear force and hold it there with the power off, it reaches for a power screw. The whole device is one idea: an inclined plane wrapped around a cylinder. Unroll one turn of thread and you are pushing a block up a ramp of rise ll and run πdm\pi d_m:

TR=Fdm2 ⁣(l+πfdmπdmfl)TL=Fdm2 ⁣(πfdmlπdm+fl)e=Fl2πTRT_R = \frac{F d_m}{2}\!\left(\frac{l + \pi f d_m}{\pi d_m - f l}\right) \qquad T_L = \frac{F d_m}{2}\!\left(\frac{\pi f d_m - l}{\pi d_m + f l}\right) \qquad e = \frac{F\,l}{2\pi T_R}

Three things to notice, one per formula:

The capacity configuration runs the relations backwards: give it your motor’s torque budget and it reports the load the screw can raise — then TLT_L tells you whether that load stays raised.

Try it

Inputs
Lead angle
Torque to raise
N·m
Torque to lower (hold back)
N·m
Raising efficiency

Governing relations

tanλ=lπdm\tan\lambda = \frac{l}{\pi d_m}

Assumes: unwrap one turn of thread at the mean diameter — the thread IS an inclined plane of rise l and run πd_m; single-start thread (for multi-start screws, l is the lead, not the pitch)

Source: Budynas, R. G., & Nisbett, J. K., Shigley's Mechanical Engineering Design, 10th ed., McGraw-Hill, 2015 — §8-2 "The Mechanics of Power Screws": Fig. 8-6 (unrolled-thread free bodies), eq. (8-1) torque to raise, eq. (8-2) torque to lower, eq. (8-3) self-locking condition πf d_m > l ⇔ f > tan λ, eq. (8-4) efficiency e = Fl/(2πT_R).

TR=Fdm2(l+πfdmπdmfl)T_R = \frac{F d_m}{2}\left(\frac{l + \pi f d_m}{\pi d_m - f l}\right)

Assumes: square thread — the normal force is not tilted by a thread half-angle (Acme threads divide the friction terms by cos 14.5°); thrust-collar friction neglected (rolling-element collar) — a plain collar can add more torque than the thread itself; steady, slow raising — friction fully developed, no dynamics · Valid while: The wedge jams: f·tan λ ≥ 1, so the harder you twist, the harder the thread presses itself into the nut — no finite torque raises the load. A thread this steep and grippy is not a power screw; back off the lead or the friction.

Source: Budynas, R. G., & Nisbett, J. K., Shigley's Mechanical Engineering Design, 10th ed., McGraw-Hill, 2015 — §8-2 "The Mechanics of Power Screws": Fig. 8-6 (unrolled-thread free bodies), eq. (8-1) torque to raise, eq. (8-2) torque to lower, eq. (8-3) self-locking condition πf d_m > l ⇔ f > tan λ, eq. (8-4) efficiency e = Fl/(2πT_R).

TL=Fdm2(πfdmlπdm+fl)T_L = \frac{F d_m}{2}\left(\frac{\pi f d_m - l}{\pi d_m + f l}\right)

Assumes: same square-thread, no-collar model with the load now helping the motion — positive T_L is torque you must apply to let the load DOWN under control · Valid while: Not self-locking — T_L has gone negative: the load can spin the screw and lower itself the moment the drive lets go (f < tan λ). Fine for a lead screw you back-drive on purpose; alarming for a jack. Hold it with a brake or pick a finer lead.

Source: Budynas, R. G., & Nisbett, J. K., Shigley's Mechanical Engineering Design, 10th ed., McGraw-Hill, 2015 — §8-2 "The Mechanics of Power Screws": Fig. 8-6 (unrolled-thread free bodies), eq. (8-1) torque to raise, eq. (8-2) torque to lower, eq. (8-3) self-locking condition πf d_m > l ⇔ f > tan λ, eq. (8-4) efficiency e = Fl/(2πT_R).

e=Fl2πTRe = \frac{F\,l}{2\pi\,T_R}

Assumes: useful work per turn (F·l) over input work per turn (2π·T_R); the frictionless screw (f = 0) would need T_0 = F·l/2π, so e = T_0/T_R

Source: Budynas, R. G., & Nisbett, J. K., Shigley's Mechanical Engineering Design, 10th ed., McGraw-Hill, 2015 — §8-2 "The Mechanics of Power Screws": Fig. 8-6 (unrolled-thread free bodies), eq. (8-1) torque to raise, eq. (8-2) torque to lower, eq. (8-3) self-locking condition πf d_m > l ⇔ f > tan λ, eq. (8-4) efficiency e = Fl/(2πT_R).

Derivation

Steps marked modeling step are where physics enters by citation — every other line is machine-proven to follow from them, and the cited models are independently re-derived in the test pipeline where possible. See what is and isn't machine-verified.

tan(lam)=lπdm\tan{\left(lam \right)} = \frac{l}{\pi d_{m}}

1. The modeling step: cut the thread along the mean diameter and unroll one full turn onto the page. What was a helix becomes an inclined plane — base πd_m (one circumference), rise l (one lead). Raising the load is pushing a block up this plane; the lead angle λ is the plane's slope. Everything below is freshman statics on that block. — unwrap the helix: thread = inclined plane modeling step

PR(fsin(lam)+cos(lam))=F(fcos(lam)+sin(lam))P_{R} \left(- f \sin{\left(lam \right)} + \cos{\left(lam \right)}\right) = F \left(f \cos{\left(lam \right)} + \sin{\left(lam \right)}\right)

2. Equilibrium of the block sliding up the plane: a horizontal push P_R, the weight F, and a fully-developed friction force f·N pointing down-slope. Summing forces along and across the plane and eliminating N gives P_R = F(sin λ + f cos λ)/(cos λ − f sin λ). (The build verifies this line is exactly equivalent to the closed form authored for T_R; the test pipeline re-derives it from the two equilibrium equations with N kept explicit.) — statics: block on the plane, eliminate N

TR=PRdm2T_{R} = \frac{P_{R} d_{m}}{2}

3. The horizontal push acts at the thread's mean radius, so the torque is P_R·d_m/2. Dividing the equilibrium result through by cos λ and substituting tan λ = l/(πd_m) turns the trigonometry into hardware numbers: T_R = (F d_m/2)·(l + πf d_m)/(πd_m − f l). — torque = push × mean radius

TL(πdm+fl)=Fdm(πdmfl)2T_{L} \left(\pi d_{m} + f l\right) = \frac{F d_{m} \left(\pi d_{m} f - l\right)}{2}

4. Run the same block DOWN the plane: gravity now helps and friction switches sides. The numerator πf d_m − l is the whole self-locking story in one subtraction — while friction outweighs the lead, T_L is positive (you must push to lower the load); the moment the lead wins, T_L flips sign and the load drives the screw. Set f to zero in the widget and watch a jack become a fan. — statics: same block, descending

2πTReff=Fl2 \pi T_{R} eff = F l

5. One turn of the screw does 2πT_R of work at the handle and lifts the load by exactly one lead, F·l of useful work. The ratio is the efficiency — and because the frictionless torque is T_0 = Fl/2π, this is also T_0/T_R. Square-thread jacks routinely run 30–50 %: the rest of your effort is heating the nut. A self-locking screw is provably under 50 % — locking is purchased with friction, and friction is purchased with work. — work out / work in

How it fails

The widget models torque equilibrium on a perfect square thread. Real power screws fail around the edges of that model:

  • Belt Drive (Flat Belt / Capstan)

    Friction compounding like interest: every degree of wrap multiplies the tension a belt can hold, e^μθ in total — the same exponential that lets a sailor check a ship with two turns of rope. At speed, centrifugal relief steals tension back, so every belt has a power ceiling.

    • torque-power
  • Planetary (Epicyclic) Gearset

    Three coaxial members — sun, ring, planet carrier — share one gear mesh law. With two degrees of freedom, it has no single "ratio": fix a different member and the same hardware becomes a different transmission.

    • kinematics
    • torque-power
  • Spur Gear Pair (Lewis Bending)

    Two meshing spur gears carry power through one tangential tooth force. The Lewis equation turns that force into a root-bending stress, and a cited form-factor table sets how much a tooth of N teeth can take. Same load, same module — yet the pinion, with fewer teeth, always works harder.

    • stress
    • torque-power
  • Axial Disk Clutch / Brake (Uniform Wear vs Uniform Pressure)

    The torque an axial plate clutch can pass depends on an assumption you cannot see: how the contact pressure is distributed across the friction annulus. A new, rigid clutch presses uniformly; a worn-in one wears until pressure ∝ 1/r, concentrating load at the inner edge. This page shows both torque predictions side by side — never picking a winner — with the worn-in model always giving the smaller (safe) number, and the r_i = r_o/√3 that squeezes the most torque from a given lining.

    • torque-power
  • Bolted Joint with Gasket (External Tensile Load)

    A preloaded bolt clamping a gasketed joint, then pulled by an external tensile load. The bolt and the members act as two springs in parallel, so the external load does NOT all go to the bolt — it splits by stiffness. The build solves the coupled bolt/member force system exactly and refuses the moment the members go slack.

    • stress
  • Helical Compression Spring

    A torsion bar wound into a package: push on the coil and the wire twists. G sets the rate, σ_y sets the margin, and the geometry trades them against three envelopes — coil bind, buckling, and a spring index you can actually wind.

    • stiffness
    • stress
    • mass-cost

Chains with

Outputs whose SI dimension and quantity kind match another THING's input — the only wires the planner's connectionLegal accepts (invariant 2, computed at build time, not hand-listed). Wire these on the chaining demo.

+ 17 more THINGs its outputs can legally feed (showing the first 8 in course order).

Sources