Planetary (Epicyclic) Gearset

kinematicstorque-power

Verified build 7 relations · 6 identities proven · 0 modeling steps · 12 parity samples

A planetary (epicyclic) gearset packs three coaxial connection points into one compact, concentric stage: a central sun gear, an internally-toothed ring gear, and a carrier that holds two or more planet gears meshing with both. You have one in every automatic transmission, most EV reduction gearboxes, wind-turbine speed increasers, cordless-drill gearboxes, and bicycle hub gears.

What makes it worth studying first: it is the simplest mechanism that has no single gear ratio. The speed relation (the Willis equation) links three speeds, so the gearset has two kinematic degrees of freedom — you must pick two speeds before the third is determined. Fix the ring and it’s a ~3.5:1 reduction; fix the sun and the same hardware gives a different ratio; fix the carrier and the output reverses; drive two members at once and it adds speeds like a differential. The widget below stores the relation, not a one-way formula — switching configurations just changes which variables you’re allowed to turn.

Two practical notes baked into the relations: the planets are idlers (their tooth count cancels out of the speed law, though it sets the ring size via Nr=Ns+2NpN_r = N_s + 2N_p), and an assembled set also needs (Ns+Nr)(N_s + N_r) divisible by the number of equally-spaced planets — with three planets, the default 24/60 set passes: (24+60)/3=28(24+60)/3 = 28.

Try it

Inputs
N·m
Ring teeth
Carrier speed
Ring torque
N·m
Carrier torque
N·m
Torque delivered to the load
N·m

Governing relations

ωsωcωrωc=NrNs\frac{\omega_s - \omega_c}{\omega_r - \omega_c} = -\frac{N_r}{N_s}

Assumes: rigid gears, no backlash or slip; all axes parallel; planets are idlers (their count and speed drop out of the speed relation)

Source: Norton, R. L., Design of Machinery: An Introduction to the Synthesis and Analysis of Mechanisms and Machines, 5th ed., McGraw-Hill, 2012 — ch. 9 (gear trains; epicyclic/Willis analysis).

Nr=Ns+2NpN_r = N_s + 2 N_p

Assumes: sun, planets, and ring share one module (tooth size) and standard external/internal meshing

Source: Norton, R. L., Design of Machinery: An Introduction to the Synthesis and Analysis of Mechanisms and Machines, 5th ed., McGraw-Hill, 2012 — ch. 9 (gear trains; epicyclic/Willis analysis).

Ts+Tr+Tc=0T_s + T_r + T_c = 0

Assumes: static equilibrium of the gearset as a free body (externally applied shaft torques)

Source: Budynas, R. G., & Nisbett, J. K., Shigley's Mechanical Engineering Design, 10th ed., McGraw-Hill, 2015 — §13-13 (planetary gear trains: force, torque, and power flow).

Tsωs+Trωr+Tcωc=0T_s\,\omega_s + T_r\,\omega_r + T_c\,\omega_c = 0

Assumes: ideal gearset — no friction losses (real planetary stages run ~96–99% efficient per mesh)

Source: Budynas, R. G., & Nisbett, J. K., Shigley's Mechanical Engineering Design, 10th ed., McGraw-Hill, 2015 — §13-13 (planetary gear trains: force, torque, and power flow).

Tr=NrNsTsT_r = \frac{N_r}{N_s} T_s

Assumes: follows from tangential force balance at the sun–planet and planet–ring meshes

Source: Budynas, R. G., & Nisbett, J. K., Shigley's Mechanical Engineering Design, 10th ed., McGraw-Hill, 2015 — §13-13 (planetary gear trains: force, torque, and power flow).

Tc=Ns+NrNsTsT_c = -\frac{N_s + N_r}{N_s} T_s

Assumes: combination of the torque balance and the mesh force balance

Source: Budynas, R. G., & Nisbett, J. K., Shigley's Mechanical Engineering Design, 10th ed., McGraw-Hill, 2015 — §13-13 (planetary gear trains: force, torque, and power flow).

Tout=TcT_{out} = -T_c

Assumes: action–reaction across the output shaft interface — T_c is the torque the carrier shaft exerts ON the gear set; the gear set exerts −T_c back on the shaft, and that is what the shaft delivers to the load

Source: Budynas, R. G., & Nisbett, J. K., Shigley's Mechanical Engineering Design, 10th ed., McGraw-Hill, 2015 — §13-13 (planetary gear trains: force, torque, and power flow).

Derivation

Steps marked modeling step are where physics enters by citation — every other line is machine-proven to follow from them, and the cited models are independently re-derived in the test pipeline where possible. See what is and isn't machine-verified.

Ns(ωc+ωs)=Nr(ωcωr)N_{s} \left(- \omega_{c} + \omega_{s}\right) = N_{r} \left(\omega_{c} - \omega_{r}\right)

1. Ride on the carrier. In that rotating frame the gearset is an ordinary two-gear train from sun to ring (through the planet idlers), so the relative speeds are locked by the tooth ratio, with a sign flip because an internal mesh reverses once. This is the Willis equation, cross-multiplied. — change to the carrier frame

Nsωs=ωc(Nr+Ns)N_{s} \omega_{s} = \omega_{c} \left(N_{r} + N_{s}\right)

2. Hold the ring still (ω_r = 0) and collect the carrier terms on one side. — apply the constraint and rearrange

ωc=NsωsNr+Ns\omega_{c} = \frac{N_{s} \omega_{s}}{N_{r} + N_{s}}

3. Solve for the carrier. The carrier always turns the same way as the sun, slower by the factor 1 + N_r/N_s — this configuration is a torque-multiplying reduction. — solve

ωsωc=Nr+NsNs\frac{\omega_{s}}{\omega_{c}} = \frac{N_{r} + N_{s}}{N_{s}}

4. The speed ratio of the stage. With the default teeth (N_s = 24, N_r = 60) the ratio is 3.5:1 — and notice it depends only on tooth counts you can read off the hardware. — form the ratio

Tr=NrTsNsT_{r} = \frac{N_{r} T_{s}}{N_{s}}

5. The same tangential tooth force acts at the sun radius and (through each planet) at the ring radius, and radii are proportional to tooth counts — so the ring reaction torque scales by N_r/N_s. — mesh force balance

Tc=Ts(Nr+Ns)NsT_{c} = - \frac{T_{s} \left(N_{r} + N_{s}\right)}{N_{s}}

6. Equilibrium of the whole gearset: the carrier shaft reacts the sum. Check the ideal power books balance: T_s ω_s + T_c ω_c = 0 exactly when the ring is stationary. — torque balance

How it fails

Planetary stages are compact because three or more planets share the load — and most of their failure modes come from that sharing being imperfect.

The torque relations in this entry assume an ideal, lossless, rigid gearset — real stages run roughly 96–99% efficient per mesh, and the lost few percent become heat in exactly the components listed above.

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Chains with

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+ 8 more THINGs its outputs can legally feed (showing the first 8 in course order).

Sources